Back to Home11/16/2025, 6:47:40 PM

Decoding Leibniz Notation (2024)

46 points
12 comments

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thoughtful

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mixed

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science

Key topics

mathematics

calculus

notation systems

Debate intensity40/100

The article 'Decoding Leibniz Notation' explores the nuances of Leibniz notation in calculus, sparking a discussion on its comparison to Lagrange notation and the implications of different notation systems.

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Light discussion

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8h

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2

Day 1

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Key moments

  1. 01Story posted

    11/16/2025, 6:47:40 PM

    3d ago

    Step 01
  2. 02First comment

    11/17/2025, 2:57:25 AM

    8h after posting

    Step 02
  3. 03Peak activity

    2 comments in Day 1

    Hottest window of the conversation

    Step 03
  4. 04Latest activity

    11/17/2025, 6:36:09 AM

    2d ago

    Step 04

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Discussion (12 comments)
Showing 2 comments of 12
GarnetFloride
2d ago
I remember reading Einstein's Relativity and having to translate the notation into what I was learning in Calculus class.
cgadski
2d ago
There's a lot of online discussion that insists Leibniz notation is just Lagrange notation with wacky conventions. This post seems to have the same conclusion, saying that df/dx should be a syntax error. I understand where this is coming from. For example, in the chain rule

dz/dx = dz/dy dy/dx,

the expression dz/dy needs to become z'(y(x)) in Lagrange notation, whereas dy/dx is just y'(x). So it's not possible to map Leibniz notation unambiguously onto Lagrange notation and it's reasonable to conclude there are "vagaries" at play.

However, I promise that this notation is totally vagary-free if you think of the problem of differentiating a _relationship_ between three variables (x, y, z). Specifically, we need to think about how a relationship between these variables "extends" to a relationship between (x, y, z, dx, dy, dz), where (dx, dy, dz) measures an infinitesimal perturbation. In differential geometry we call that operation a "prolongation." Then it makes perfect sense to write an equation like

dz/dx = 4 y.

That just means that, for any infinitesimal nudge we can make to (x, y, z) while respecting our relationship, z gets moved at 4 y times the rate that we moved x. We could also write dz = 4 y dx. If our relationship has one degree of freedom, it is then easy to show that dz/dx = dz/dy dy/dx at any point where all these fractions are well-defined. It's also true that, when our relationship has two degrees of freedom and we modify the "fractions" dz/dx to be such that dz = dz/dx dx + dz/dy dy, then

dz/dx = -dz/dy dy/dx,

which is a formula that can't be copied into Lagrange notation so far as I know.

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ID: 45947374Type: storyLast synced: 11/19/2025, 7:08:55 PM

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